财务管理与财务分析运营管理课件c(编辑修改稿)内容摘要:
ve… Mean = T Variance = T 169。 2020 Pearson Education The exponential distribution describes the probability that the service time will be no more than T time periods. Probability Distributions Service time If the customer service rate is three per hour, what is the probability that a customer requires less than 10 minutes of service? P(t ≤T) = 1 – eT μ = average number of customers pleting service per period t = service time of the customer T = target service time P(t ≤ hr) = 1 – e3() = 1 – = Example Mean = 1/ Variance = (1/ )2 169。 2020 Pearson Education Operating Characteristics Line Length: Number of customers in line. Number of Customers in System: Includes customers in line and being serviced. Waiting Time in Line: Waiting for service to begin. Total Time in System: Elapsed time between entering the line and exiting the system. Service Facility Utilization: Reflects the percentage of time servers are busy. 169。 2020 Pearson Education SingleServer Model The simplest waiting line model involves a single server and a single line of customers. Assumptions: The customer population is infinite and patient. The customers arrive according to a Poisson distribution, with a mean arrival rate of The service distribution is exponential with a mean service rate of The mean service rate exceeds the mean arrival rate. Customers are served on a firste, firstserved basis. The length of the waiting line is unlimited. 169。 2020 Pearson Education = Average utilization of the system = L = Average number of customers in the service system = – Lq = Average number of customers in the waiting line = L W = Average time spent in the system, including service = 1 – Wq = Average waiting time in line = W Rn = Probability that n customers are in the system = (1 – )n SingleServer Model 169。 2020 Pearson Education SingleChannel, SinglePhase System Arrival rate ( = 30/hour, Service rate ( = 35/hour Average time in line = Wq = () = hour, or minutes Average time in system = W = = hour, or 12 minutes 1 35 – 30 Average number in line = Lq = (6) = customers Average number in system。财务管理与财务分析运营管理课件c(编辑修改稿)
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rocesses deliver value to external customers. Support processes provide vital inputs for the core processes. 169。 2020 Pearson Education Core Processes 1. Customer relationship processes Identify,
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d according to its perceived importance, with the total weights typically equaling 100. The total score is the sum of the weighted scores (weight score) for all the criteria. The manager can pare
2020 Pearson Education Core petence examples Starwood case: page 19 Franchising franchisee franchisor service fee: McDonald 4% monthly sales Consistency 169。 2020 Pearson Education Global
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if (*pf%2 amp。 amp。 *pf*11%25632) *pf = *pf*11%256。 pf++。 } } } 题目 19:编写一个函数 findstr(),该函数统计一个长度为 2 的子字符串在另一个字符串中出现的次数。 例如:假定输入的字 符串为asd asasdfg asd as zx67 asd mklo,子字符串为 as,函数返回值为 6。 函数