Draft Report-L'OREAL内容摘要:
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m+ an= 2 ak. (2) 已知 { an} 是等差数列 , 若 a3+ a4+ a5+ a6+ a7= 450 , 求 a2+ a8. 【思路分析】 依性质 (6) 若 m + n = p + q ,则 am+ an= ap+aq解答. 【解析】 ∵ a3+ a7= a4+ a6= 2 a5= a2+ a8, ∴ a3+ a4+ a5+ a6+ a7= 5 a5= 450 ⇒ a5=
mBmAmBmABmAm1020 1 0 02)2(30 222 ∴ S3m=A(3m)2+B3 m=210 解法三:根据等差数列性质知: Sm,S2m-Sm,S3m- S2m也成等差数列,从而有: 2(S2m- Sm)=Sm+(S3m- S2m) ∴ S3m=3(S2m- Sm)=210 解法四:令 m=1得 S1=30, S2=100,得a1=30,a1+a2=100,∴
式的解法 先整理成标准型f x g x 0(0) 或f x g x ≥ 0( ≤ 0) ,再化成整式不等式来解; (1)f x g x 0 ⇔ f ( x ) g ( x )0 ; (2)f x g x 0 ⇔ f ( x ) g ( x )0 ; (3)f x g x ≥ 0 ⇔ f x g x ≥ 0 ,g